7/2=(x+3)/6

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Solution for 7/2=(x+3)/6 equation: 



7/2=(x+3)/6

We move all terms to the left:

7/2-((x+3)/6)=0

We calculate fractions


(-((x+3)*2)/()+()/()=0



We calculate terms in parentheses: +(-((x+3)*2)/()+()/(), so:

-((x+3)*2)/()+()/(

We add all the numbers together, and all the variables

-((x+3)*2)/()+1

We multiply all the terms by the denominator


-((x+3)*2)+1*()



We calculate terms in parentheses: -((x+3)*2), so:

(x+3)*2

We multiply parentheses

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

-(2x+6)

We get rid of parentheses

-2x-6

Back to the equation:

+(-2x-6)



We get rid of parentheses

-2x-6=0

We move all terms containing x to the left, all other terms to the right

-2x=6

x=6/-2

x=-3

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