7/2(m+2)=5/2(20+m)

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Solution for 7/2(m+2)=5/2(20+m) equation: 



7/2(m+2)=5/2(20+m)

We move all terms to the left:

7/2(m+2)-(5/2(20+m))=0



Domain of the equation: 2(m+2)!=0

m∈R





Domain of the equation: 2(20+m))!=0

m∈R



We add all the numbers together, and all the variables

7/2(m+2)-(5/2(m+20))=0

We calculate fractions


(14mm/(2(m+2)*2(m+20)))+(-10mm/(2(m+2)*2(m+20)))=0



We calculate terms in parentheses: +(14mm/(2(m+2)*2(m+20))), so:

14mm/(2(m+2)*2(m+20))

We multiply all the terms by the denominator


14mm

Back to the equation:

+(14mm)





We calculate terms in parentheses: +(-10mm/(2(m+2)*2(m+20))), so:

-10mm/(2(m+2)*2(m+20))

We multiply all the terms by the denominator


-10mm

Back to the equation:

+(-10mm)



We get rid of parentheses

14mm-10mm=0

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