7/2(3x-5)=1/4(42x-8)-31/2

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Solution for 7/2(3x-5)=1/4(42x-8)-31/2 equation: 


x in (-oo:+oo)

(7/2)*(3*x-5) = (1/4)*(42*x-8)-(31/2) // - (1/4)*(42*x-8)-(31/2)

(7/2)*(3*x-5)-((1/4)*(42*x-8))+31/2 = 0

(7/2)*(3*x-5)+(-1/4)*(42*x-8)+31/2 = 0

7/2*(3*x-5)-1/4*(42*x-8)+31/2 = 0

(2*7/2*(3*x-5))/2+(-1/4*2*(42*x-8))/2+31/2 = 0

2*7/2*(3*x-5)-1/4*2*(42*x-8)+31 = 0

31-31 = 0

0 = 0

0/2 = 0

0/2 = 0 // * 2

0 = 0

0 = 0

x należy do R

x in (-oo:+oo)

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