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7/10w-18=26/1w
We move all terms to the left:
7/10w-18-(26/1w)=0
Domain of the equation: 10w!=0
w!=0/10
w!=0
w∈R
Domain of the equation: 1w)!=0We add all the numbers together, and all the variables
w!=0/1
w!=0
w∈R
7/10w-(+26/1w)-18=0
We get rid of parentheses
7/10w-26/1w-18=0
We calculate fractions
7w/10w^2+(-260w)/10w^2-18=0
We multiply all the terms by the denominator
7w+(-260w)-18*10w^2=0
Wy multiply elements
-180w^2+7w+(-260w)=0
We get rid of parentheses
-180w^2+7w-260w=0
We add all the numbers together, and all the variables
-180w^2-253w=0
a = -180; b = -253; c = 0;
Δ = b2-4ac
Δ = -2532-4·(-180)·0
Δ = 64009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64009}=253$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-253)-253}{2*-180}=\frac{0}{-360} =0 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-253)+253}{2*-180}=\frac{506}{-360} =-1+73/180 $
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