7/10c-81/2c=-16

Solution for 7/10c-81/2c=-16 equation:

7/10c-81/2c=-16

We move all terms to the left:

7/10c-81/2c-(-16)=0


Domain of the equation: 10c!=0

c!=0/10

c!=0

c∈R



Domain of the equation: 2c!=0

c!=0/2

c!=0

c∈R


We add all the numbers together, and all the variables

7/10c-81/2c+16=0

We calculate fractions


14c/20c^2+(-810c)/20c^2+16=0

We multiply all the terms by the denominator


14c+(-810c)+16*20c^2=0

Wy multiply elements

320c^2+14c+(-810c)=0

We get rid of parentheses

320c^2+14c-810c=0

We add all the numbers together, and all the variables

320c^2-796c=0

a = 320; b = -796; c = 0;
Δ = b2-4ac
Δ = -7962-4·320·0
Δ = 633616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{633616}=796$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-796)-796}{2*320}=\frac{0}{640}
=0
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-796)+796}{2*320}=\frac{1592}{640}
=2+39/80
$