7/10(x-3y-5z)

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Solution for 7/10(x-3y-5z) equation: 


x in (-oo:+oo)

(7/10)*(x-(3*y)-(5*z)) = 0

(7/10)*(x-3*y-5*z) = 0

7/10*(x-3*y-5*z) = 0

( 7/10 )

7/10 = 0

x belongs to the empty set

( x-3*y-5*z )

x-3*y-5*z = 0 // + -3*y-5*z

x = -(-3*y-5*z)

x = -(-3*y-5*z)

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