7/(x-3)=3/(x+8)

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Solution for 7/(x-3)=3/(x+8) equation: 



7/(x-3)=3/(x+8)

We move all terms to the left:

7/(x-3)-(3/(x+8))=0



Domain of the equation: (x-3)!=0

We move all terms containing x to the left, all other terms to the right

x!=3

x∈R





Domain of the equation: (x+8))!=0

x∈R



We calculate fractions


7x/((x-3)*(x+8)))+(-(3*(x-3))/((x-3)*(x+8)))=0



We calculate terms in parentheses: -(3*(x-3))/((x-3)*(x+8))), so:

3*(x-3))/((x-3)*(x+8))

We multiply all the terms by the denominator


3*(x-3))

We multiply parentheses

3x+

We add all the numbers together, and all the variables

3x

Back to the equation:

-(3x)



We add all the numbers together, and all the variables

-3x+7x/((x-3)*(x+8)))+(=0

We multiply all the terms by the denominator


-3x*((x-3)*(x+8)))+(+7x=0

We add all the numbers together, and all the variables

7x-3x*((x-3)*(x+8)))+(=0

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