7/(x+1)=5/(x-3)

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Solution for 7/(x+1)=5/(x-3) equation: 


D( x )

x-3 = 0

x+1 = 0

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:3) U (3:+oo)

7/(x+1) = 5/(x-3) // - 5/(x-3)

7/(x+1)-(5/(x-3)) = 0

7/(x+1)-5*(x-3)^-1 = 0

7/(x+1)-5/(x-3) = 0

(7*(x-3))/((x+1)*(x-3))+(-5*(x+1))/((x+1)*(x-3)) = 0

7*(x-3)-5*(x+1) = 0

2*x-26 = 0

(2*x-26)/((x+1)*(x-3)) = 0

(2*x-26)/((x+1)*(x-3)) = 0 // * (x+1)*(x-3)

2*x-26 = 0

2*x-26 = 0 // + 26

2*x = 26 // : 2

x = 26/2

x = 13

x = 13

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