7/(a-1)=5/(a+3)

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Solution for 7/(a-1)=5/(a+3) equation:



7/(a-1)=5/(a+3)
We move all terms to the left:
7/(a-1)-(5/(a+3))=0
Domain of the equation: (a-1)!=0
We move all terms containing a to the left, all other terms to the right
a!=1
a∈R
Domain of the equation: (a+3))!=0
a∈R
We calculate fractions
7a/((a-1)*(a+3)))+(-(5*(a-1))/((a-1)*(a+3)))=0
We calculate terms in parentheses: -(5*(a-1))/((a-1)*(a+3))), so:
5*(a-1))/((a-1)*(a+3))
We multiply all the terms by the denominator
5*(a-1))
We multiply parentheses
5a+
We add all the numbers together, and all the variables
5a
Back to the equation:
-(5a)
We add all the numbers together, and all the variables
-5a+7a/((a-1)*(a+3)))+(=0
We multiply all the terms by the denominator
-5a*((a-1)*(a+3)))+(+7a=0
We add all the numbers together, and all the variables
7a-5a*((a-1)*(a+3)))+(=0

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