7/(4x+2)=6/(5x+3)

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Solution for 7/(4x+2)=6/(5x+3) equation:


D( x )

5*x+3 = 0

4*x+2 = 0

5*x+3 = 0

5*x+3 = 0

5*x+3 = 0 // - 3

5*x = -3 // : 5

x = -3/5

4*x+2 = 0

4*x+2 = 0

4*x+2 = 0 // - 2

4*x = -2 // : 4

x = -2/4

x = -1/2

x in (-oo:-3/5) U (-3/5:-1/2) U (-1/2:+oo)

7/(4*x+2) = 6/(5*x+3) // - 6/(5*x+3)

7/(4*x+2)-(6/(5*x+3)) = 0

7/(4*x+2)-6*(5*x+3)^-1 = 0

7/(4*x+2)-6/(5*x+3) = 0

(7*(5*x+3))/((4*x+2)*(5*x+3))+(-6*(4*x+2))/((4*x+2)*(5*x+3)) = 0

7*(5*x+3)-6*(4*x+2) = 0

11*x+9 = 0

(11*x+9)/((4*x+2)*(5*x+3)) = 0

(11*x+9)/((4*x+2)*(5*x+3)) = 0 // * (4*x+2)*(5*x+3)

11*x+9 = 0

11*x+9 = 0 // - 9

11*x = -9 // : 11

x = -9/11

x = -9/11

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