7/(2x-3)=4/(x+3)

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Solution for 7/(2x-3)=4/(x+3) equation: 


D( x )

2*x-3 = 0

x+3 = 0

2*x-3 = 0

2*x-3 = 0

2*x-3 = 0 // + 3

2*x = 3 // : 2

x = 3/2

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:3/2) U (3/2:+oo)

7/(2*x-3) = 4/(x+3) // - 4/(x+3)

7/(2*x-3)-(4/(x+3)) = 0

7/(2*x-3)-4*(x+3)^-1 = 0

7/(2*x-3)-4/(x+3) = 0

(7*(x+3))/((2*x-3)*(x+3))+(-4*(2*x-3))/((2*x-3)*(x+3)) = 0

7*(x+3)-4*(2*x-3) = 0

33-x = 0

(33-x)/((2*x-3)*(x+3)) = 0

(33-x)/((2*x-3)*(x+3)) = 0 // * (2*x-3)*(x+3)

33-x = 0

33-x = 0 // - 33

-x = -33 // * -1

x = 33

x = 33

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