7-7/8(16x-40)=3/4(8x-12)

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Solution for 7-7/8(16x-40)=3/4(8x-12) equation: 


x in (-oo:+oo)

7-((7/8)*(16*x-40)) = (3/4)*(8*x-12) // - (3/4)*(8*x-12)

7-((7/8)*(16*x-40))-((3/4)*(8*x-12)) = 0

(-7/8)*(16*x-40)+(-3/4)*(8*x-12)+7 = 0

7-7/8*(16*x-40)-3/4*(8*x-12) = 0

7-7/8*(16*x-40)-3/4*(8*x-12) = 0

7-20*x+44 = 0

51-20*x = 0

51-20*x = 0

51-20*x = 0 // - 51

-20*x = -51 // : -20

x = -51/(-20)

x = 51/20

x = 51/20

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