7-6(r-1)+3(3-4r)=7+(7r-4)

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Solution for 7-6(r-1)+3(3-4r)=7+(7r-4) equation: 



7-6(r-1)+3(3-4r)=7+(7r-4)

We move all terms to the left:

7-6(r-1)+3(3-4r)-(7+(7r-4))=0

We add all the numbers together, and all the variables

-6(r-1)+3(-4r+3)-(7+(7r-4))+7=0

We multiply parentheses

-6r-12r-(7+(7r-4))+6+9+7=0



We calculate terms in parentheses: -(7+(7r-4)), so:

7+(7r-4)

determiningTheFunctionDomain
(7r-4)+7

We get rid of parentheses

7r-4+7

We add all the numbers together, and all the variables

7r+3

Back to the equation:

-(7r+3)



We add all the numbers together, and all the variables

-18r-(7r+3)+22=0

We get rid of parentheses

-18r-7r-3+22=0

We add all the numbers together, and all the variables

-25r+19=0

We move all terms containing r to the left, all other terms to the right

-25r=-19

r=-19/-25

r=19/25

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