7-5a=7(1-3a)+2a

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Solution for 7-5a=7(1-3a)+2a equation: 



7-5a=7(1-3a)+2a

We move all terms to the left:

7-5a-(7(1-3a)+2a)=0

We add all the numbers together, and all the variables

-5a-(7(-3a+1)+2a)+7=0



We calculate terms in parentheses: -(7(-3a+1)+2a), so:

7(-3a+1)+2a

We add all the numbers together, and all the variables

2a+7(-3a+1)

We multiply parentheses

2a-21a+7

We add all the numbers together, and all the variables

-19a+7

Back to the equation:

-(-19a+7)



We get rid of parentheses

-5a+19a-7+7=0

We add all the numbers together, and all the variables

14a=0

a=0/14

a=0

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