7-5(x+1)=4-2(x+4)

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Solution for 7-5(x+1)=4-2(x+4) equation: 



7-5(x+1)=4-2(x+4)

We move all terms to the left:

7-5(x+1)-(4-2(x+4))=0

We multiply parentheses

-5x-(4-2(x+4))-5+7=0



We calculate terms in parentheses: -(4-2(x+4)), so:

4-2(x+4)

determiningTheFunctionDomain
-2(x+4)+4

We multiply parentheses

-2x-8+4

We add all the numbers together, and all the variables

-2x-4

Back to the equation:

-(-2x-4)



We add all the numbers together, and all the variables

-5x-(-2x-4)+2=0

We get rid of parentheses

-5x+2x+4+2=0

We add all the numbers together, and all the variables

-3x+6=0

We move all terms containing x to the left, all other terms to the right

-3x=-6

x=-6/-3

x=+2

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