7-3*(2x-4)=2x+1+3*(3-x)

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Solution for 7-3*(2x-4)=2x+1+3*(3-x) equation: 



7-3(2x-4)=2x+1+3(3-x)

We move all terms to the left:

7-3(2x-4)-(2x+1+3(3-x))=0

We add all the numbers together, and all the variables

-3(2x-4)-(2x+1+3(-1x+3))+7=0

We multiply parentheses

-6x-(2x+1+3(-1x+3))+12+7=0



We calculate terms in parentheses: -(2x+1+3(-1x+3)), so:

2x+1+3(-1x+3)

determiningTheFunctionDomain
2x+3(-1x+3)+1

We multiply parentheses

2x-3x+9+1

We add all the numbers together, and all the variables

-1x+10

Back to the equation:

-(-1x+10)



We add all the numbers together, and all the variables

-6x-(-1x+10)+19=0

We get rid of parentheses

-6x+1x-10+19=0

We add all the numbers together, and all the variables

-5x+9=0

We move all terms containing x to the left, all other terms to the right

-5x=-9

x=-9/-5

x=1+4/5

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