7-3(2x+5)=8x-2(9-4x)

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Solution for 7-3(2x+5)=8x-2(9-4x) equation: 



7-3(2x+5)=8x-2(9-4x)

We move all terms to the left:

7-3(2x+5)-(8x-2(9-4x))=0

We add all the numbers together, and all the variables

-3(2x+5)-(8x-2(-4x+9))+7=0

We multiply parentheses

-6x-(8x-2(-4x+9))-15+7=0



We calculate terms in parentheses: -(8x-2(-4x+9)), so:

8x-2(-4x+9)

We multiply parentheses

8x+8x-18

We add all the numbers together, and all the variables

16x-18

Back to the equation:

-(16x-18)



We add all the numbers together, and all the variables

-6x-(16x-18)-8=0

We get rid of parentheses

-6x-16x+18-8=0

We add all the numbers together, and all the variables

-22x+10=0

We move all terms containing x to the left, all other terms to the right

-22x=-10

x=-10/-22

x=5/11

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