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7-1/6x=10/3x
We move all terms to the left:
7-1/6x-(10/3x)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-1/6x-(+10/3x)+7=0
We get rid of parentheses
-1/6x-10/3x+7=0
We calculate fractions
(-3x)/18x^2+(-60x)/18x^2+7=0
We multiply all the terms by the denominator
(-3x)+(-60x)+7*18x^2=0
Wy multiply elements
126x^2+(-3x)+(-60x)=0
We get rid of parentheses
126x^2-3x-60x=0
We add all the numbers together, and all the variables
126x^2-63x=0
a = 126; b = -63; c = 0;
Δ = b2-4ac
Δ = -632-4·126·0
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3969}=63$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-63}{2*126}=\frac{0}{252} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+63}{2*126}=\frac{126}{252} =1/2 $
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