7-1/2(8y-3)=10-4/5(3-4y)

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Solution for 7-1/2(8y-3)=10-4/5(3-4y) equation: 



7-1/2(8y-3)=10-4/5(3-4y)

We move all terms to the left:

7-1/2(8y-3)-(10-4/5(3-4y))=0



Domain of the equation: 2(8y-3)!=0

y∈R





Domain of the equation: 5(3-4y))!=0

y∈R



We add all the numbers together, and all the variables

-1/2(8y-3)-(10-4/5(-4y+3))+7=0

We calculate fractions


(-5y(-)/(2(8y-3)*5(-4y+3)))+(-(-8y8)/(2(8y-3)*5(-4y+3)))+7=0



We calculate terms in parentheses: +(-5y(-)/(2(8y-3)*5(-4y+3))), so:

-5y(-)/(2(8y-3)*5(-4y+3))

We add all the numbers together, and all the variables

-5y0/(2(8y-3)*5(-4y+3))

We multiply all the terms by the denominator


-5y0

We add all the numbers together, and all the variables

-5y

Back to the equation:

+(-5y)





We calculate terms in parentheses: +(-(-8y8)/(2(8y-3)*5(-4y+3))), so:

-(-8y8)/(2(8y-3)*5(-4y+3))

We add all the numbers together, and all the variables

-(-8y^8)/(2(8y-3)*5(-4y+3))

We multiply all the terms by the denominator


-(-8y^8)

We do not support eypression: y^8

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