7-(x-3)+3x=6(x-5)+x

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Solution for 7-(x-3)+3x=6(x-5)+x equation: 



7-(x-3)+3x=6(x-5)+x

We move all terms to the left:

7-(x-3)+3x-(6(x-5)+x)=0

We add all the numbers together, and all the variables

3x-(x-3)-(6(x-5)+x)+7=0

We get rid of parentheses

3x-x-(6(x-5)+x)+3+7=0



We calculate terms in parentheses: -(6(x-5)+x), so:

6(x-5)+x

We add all the numbers together, and all the variables

x+6(x-5)

We multiply parentheses

x+6x-30

We add all the numbers together, and all the variables

7x-30

Back to the equation:

-(7x-30)



We add all the numbers together, and all the variables

2x-(7x-30)+10=0

We get rid of parentheses

2x-7x+30+10=0

We add all the numbers together, and all the variables

-5x+40=0

We move all terms containing x to the left, all other terms to the right

-5x=-40

x=-40/-5

x=+8

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