7-(x+2)-3-(x-8)+2x=3-(4x+10)

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Solution for 7-(x+2)-3-(x-8)+2x=3-(4x+10) equation: 



7-(x+2)-3-(x-8)+2x=3-(4x+10)

We move all terms to the left:

7-(x+2)-3-(x-8)+2x-(3-(4x+10))=0

We add all the numbers together, and all the variables

2x-(x+2)-(x-8)-(3-(4x+10))+4=0

We get rid of parentheses

2x-x-x-(3-(4x+10))-2+8+4=0



We calculate terms in parentheses: -(3-(4x+10)), so:

3-(4x+10)

determiningTheFunctionDomain
-(4x+10)+3

We get rid of parentheses

-4x-10+3

We add all the numbers together, and all the variables

-4x-7

Back to the equation:

-(-4x-7)



We add all the numbers together, and all the variables

-(-4x-7)+10=0

We get rid of parentheses

4x+7+10=0

We add all the numbers together, and all the variables

4x+17=0

We move all terms containing x to the left, all other terms to the right

4x=-17

x=-17/4

x=-4+1/4

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