7-(b+5)=8b-2

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Solution for 7-(b+5)=8b-2 equation: 



7-(b+5)=8b-2

We move all terms to the left:

7-(b+5)-(8b-2)=0

We get rid of parentheses

-b-8b-5+2+7=0

We add all the numbers together, and all the variables

-9b+4=0

We move all terms containing b to the left, all other terms to the right

-9b=-4

b=-4/-9

b=4/9

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