7-(4k-2)=2(k+3)

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Solution for 7-(4k-2)=2(k+3) equation: 



7-(4k-2)=2(k+3)

We move all terms to the left:

7-(4k-2)-(2(k+3))=0

We get rid of parentheses

-4k-(2(k+3))+2+7=0



We calculate terms in parentheses: -(2(k+3)), so:

2(k+3)

We multiply parentheses

2k+6

Back to the equation:

-(2k+6)



We add all the numbers together, and all the variables

-4k-(2k+6)+9=0

We get rid of parentheses

-4k-2k-6+9=0

We add all the numbers together, and all the variables

-6k+3=0

We move all terms containing k to the left, all other terms to the right

-6k=-3

k=-3/-6

k=1/2

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