7-(3x+2)=5x-2(x+1)

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Solution for 7-(3x+2)=5x-2(x+1) equation: 



7-(3x+2)=5x-2(x+1)

We move all terms to the left:

7-(3x+2)-(5x-2(x+1))=0

We get rid of parentheses

-3x-(5x-2(x+1))-2+7=0



We calculate terms in parentheses: -(5x-2(x+1)), so:

5x-2(x+1)

We multiply parentheses

5x-2x-2

We add all the numbers together, and all the variables

3x-2

Back to the equation:

-(3x-2)



We add all the numbers together, and all the variables

-3x-(3x-2)+5=0

We get rid of parentheses

-3x-3x+2+5=0

We add all the numbers together, and all the variables

-6x+7=0

We move all terms containing x to the left, all other terms to the right

-6x=-7

x=-7/-6

x=1+1/6

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