7+5(x-3)=3(x-2)

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Solution for 7+5(x-3)=3(x-2) equation: 



7+5(x-3)=3(x-2)

We move all terms to the left:

7+5(x-3)-(3(x-2))=0

We multiply parentheses

5x-(3(x-2))-15+7=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

5x-(3x-6)-8=0

We get rid of parentheses

5x-3x+6-8=0

We add all the numbers together, and all the variables

2x-2=0

We move all terms containing x to the left, all other terms to the right

2x=2

x=2/2

x=1

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