7+40=3(4+24a)

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Solution for 7+40=3(4+24a) equation: 



7+40=3(4+24a)

We move all terms to the left:

7+40-(3(4+24a))=0

We add all the numbers together, and all the variables

-(3(24a+4))+7+40=0

We add all the numbers together, and all the variables

-(3(24a+4))+47=0



We calculate terms in parentheses: -(3(24a+4)), so:

3(24a+4)

We multiply parentheses

72a+12

Back to the equation:

-(72a+12)



We get rid of parentheses

-72a-12+47=0

We add all the numbers together, and all the variables

-72a+35=0

We move all terms containing a to the left, all other terms to the right

-72a=-35

a=-35/-72

a=35/72

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