7+4(y+2)=21

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Solution for 7+4(y+2)=21 equation: 



7+4(y+2)=21

We move all terms to the left:

7+4(y+2)-(21)=0

We add all the numbers together, and all the variables

4(y+2)-14=0

We multiply parentheses

4y+8-14=0

We add all the numbers together, and all the variables

4y-6=0

We move all terms containing y to the left, all other terms to the right

4y=6

y=6/4

y=1+1/2

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