7+4(3x-5)=-3(4x-1)+6x

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Solution for 7+4(3x-5)=-3(4x-1)+6x equation: 



7+4(3x-5)=-3(4x-1)+6x

We move all terms to the left:

7+4(3x-5)-(-3(4x-1)+6x)=0

We multiply parentheses

12x-(-3(4x-1)+6x)-20+7=0



We calculate terms in parentheses: -(-3(4x-1)+6x), so:

-3(4x-1)+6x

We add all the numbers together, and all the variables

6x-3(4x-1)

We multiply parentheses

6x-12x+3

We add all the numbers together, and all the variables

-6x+3

Back to the equation:

-(-6x+3)



We add all the numbers together, and all the variables

12x-(-6x+3)-13=0

We get rid of parentheses

12x+6x-3-13=0

We add all the numbers together, and all the variables

18x-16=0

We move all terms containing x to the left, all other terms to the right

18x=16

x=16/18

x=8/9

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