7+3x=3(-x+2)-41

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Solution for 7+3x=3(-x+2)-41 equation: 



7+3x=3(-x+2)-41

We move all terms to the left:

7+3x-(3(-x+2)-41)=0

We add all the numbers together, and all the variables

3x-(3(-1x+2)-41)+7=0



We calculate terms in parentheses: -(3(-1x+2)-41), so:

3(-1x+2)-41

We multiply parentheses

-3x+6-41

We add all the numbers together, and all the variables

-3x-35

Back to the equation:

-(-3x-35)



We get rid of parentheses

3x+3x+35+7=0

We add all the numbers together, and all the variables

6x+42=0

We move all terms containing x to the left, all other terms to the right

6x=-42

x=-42/6

x=-7

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