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7+3/5(10-35x)=5
We move all terms to the left:
7+3/5(10-35x)-(5)=0
Domain of the equation: 5(10-35x)!=0We add all the numbers together, and all the variables
x∈R
3/5(-35x+10)+7-5=0
We add all the numbers together, and all the variables
3/5(-35x+10)+2=0
We multiply all the terms by the denominator
2*5(-35x+10)+3=0
Wy multiply elements
10x(-+3=0
We use the square of the difference formula
10x(-3=0
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