7+3(x-4)=2(10+x)

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Solution for 7+3(x-4)=2(10+x) equation: 



7+3(x-4)=2(10+x)

We move all terms to the left:

7+3(x-4)-(2(10+x))=0

We add all the numbers together, and all the variables

3(x-4)-(2(x+10))+7=0

We multiply parentheses

3x-(2(x+10))-12+7=0



We calculate terms in parentheses: -(2(x+10)), so:

2(x+10)

We multiply parentheses

2x+20

Back to the equation:

-(2x+20)



We add all the numbers together, and all the variables

3x-(2x+20)-5=0

We get rid of parentheses

3x-2x-20-5=0

We add all the numbers together, and all the variables

x-25=0

We move all terms containing x to the left, all other terms to the right

x=25

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