7+3(5y-4)=-2(4y-2)+8y

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Solution for 7+3(5y-4)=-2(4y-2)+8y equation: 



7+3(5y-4)=-2(4y-2)+8y

We move all terms to the left:

7+3(5y-4)-(-2(4y-2)+8y)=0

We multiply parentheses

15y-(-2(4y-2)+8y)-12+7=0



We calculate terms in parentheses: -(-2(4y-2)+8y), so:

-2(4y-2)+8y

We add all the numbers together, and all the variables

8y-2(4y-2)

We multiply parentheses

8y-8y+4

We add all the numbers together, and all the variables

4

Back to the equation:

-(4)



We add all the numbers together, and all the variables

15y-9=0

We move all terms containing y to the left, all other terms to the right

15y=9

y=9/15

y=3/5

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