7+3(3y-1)=34+4y

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Solution for 7+3(3y-1)=34+4y equation: 



7+3(3y-1)=34+4y

We move all terms to the left:

7+3(3y-1)-(34+4y)=0

We add all the numbers together, and all the variables

3(3y-1)-(4y+34)+7=0

We multiply parentheses

9y-(4y+34)-3+7=0

We get rid of parentheses

9y-4y-34-3+7=0

We add all the numbers together, and all the variables

5y-30=0

We move all terms containing y to the left, all other terms to the right

5y=30

y=30/5

y=6

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