7+3(2m+4)=5(2m-1)

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Solution for 7+3(2m+4)=5(2m-1) equation: 



7+3(2m+4)=5(2m-1)

We move all terms to the left:

7+3(2m+4)-(5(2m-1))=0

We multiply parentheses

6m-(5(2m-1))+12+7=0



We calculate terms in parentheses: -(5(2m-1)), so:

5(2m-1)

We multiply parentheses

10m-5

Back to the equation:

-(10m-5)



We add all the numbers together, and all the variables

6m-(10m-5)+19=0

We get rid of parentheses

6m-10m+5+19=0

We add all the numbers together, and all the variables

-4m+24=0

We move all terms containing m to the left, all other terms to the right

-4m=-24

m=-24/-4

m=+6

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