7+3(1+x)=5+-2(3+-4x)

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Solution for 7+3(1+x)=5+-2(3+-4x) equation: 



7+3(1+x)=5+-2(3+-4x)

We move all terms to the left:

7+3(1+x)-(5+-2(3+-4x))=0

We add all the numbers together, and all the variables

3(x+1)-(5+-2(-4x))+7=0

We use the square of the difference formula

3(x+1)-(5-2(-4x))+7=0

We multiply parentheses

3x-(5-2(-4x))+3+7=0



We calculate terms in parentheses: -(5-2(-4x)), so:

5-2(-4x)

determiningTheFunctionDomain
-2(-4x)+5

We multiply parentheses

8x+5

Back to the equation:

-(8x+5)



We add all the numbers together, and all the variables

3x-(8x+5)+10=0

We get rid of parentheses

3x-8x-5+10=0

We add all the numbers together, and all the variables

-5x+5=0

We move all terms containing x to the left, all other terms to the right

-5x=-5

x=-5/-5

x=1

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