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7+2/5y=3/5y
We move all terms to the left:
7+2/5y-(3/5y)=0
Domain of the equation: 5y!=0
y!=0/5
y!=0
y∈R
Domain of the equation: 5y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
2/5y-(+3/5y)+7=0
We get rid of parentheses
2/5y-3/5y+7=0
We multiply all the terms by the denominator
7*5y+2-3=0
We add all the numbers together, and all the variables
7*5y-1=0
Wy multiply elements
35y-1=0
We move all terms containing y to the left, all other terms to the right
35y=1
y=1/35
y=1/35
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