7+2(x+1)/3=8x/5

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Solution for 7+2(x+1)/3=8x/5 equation: 


x in (-oo:+oo)

(2*(x+1))/3+7 = (8*x)/5 // - (8*x)/5

(2*(x+1))/3-((8*x)/5)+7 = 0

(2*(x+1))/3+(-8/5)*x+7 = 0

(2*(x+1))/3+(-8*x)/5+7 = 0

(2*5*(x+1))/(3*5)+(-8*3*x)/(3*5)+(3*5*7)/(3*5) = 0

2*5*(x+1)-8*3*x+3*5*7 = 0

10-14*x+105 = 0

115-14*x = 0

(115-14*x)/(3*5) = 0

(115-14*x)/(3*5) = 0 // * 3*5

115-14*x = 0

115-14*x = 0 // - 115

-14*x = -115 // : -14

x = -115/(-14)

x = 115/14

x = 115/14

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