7+2(6u-7)=-3(3u-1)+3u

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Solution for 7+2(6u-7)=-3(3u-1)+3u equation: 



7+2(6u-7)=-3(3u-1)+3u

We move all terms to the left:

7+2(6u-7)-(-3(3u-1)+3u)=0

We multiply parentheses

12u-(-3(3u-1)+3u)-14+7=0



We calculate terms in parentheses: -(-3(3u-1)+3u), so:

-3(3u-1)+3u

We add all the numbers together, and all the variables

3u-3(3u-1)

We multiply parentheses

3u-9u+3

We add all the numbers together, and all the variables

-6u+3

Back to the equation:

-(-6u+3)



We add all the numbers together, and all the variables

12u-(-6u+3)-7=0

We get rid of parentheses

12u+6u-3-7=0

We add all the numbers together, and all the variables

18u-10=0

We move all terms containing u to the left, all other terms to the right

18u=10

u=10/18

u=5/9

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