7+2(4u-2)=-3(3u-4)+5u

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Solution for 7+2(4u-2)=-3(3u-4)+5u equation: 



7+2(4u-2)=-3(3u-4)+5u

We move all terms to the left:

7+2(4u-2)-(-3(3u-4)+5u)=0

We multiply parentheses

8u-(-3(3u-4)+5u)-4+7=0



We calculate terms in parentheses: -(-3(3u-4)+5u), so:

-3(3u-4)+5u

We add all the numbers together, and all the variables

5u-3(3u-4)

We multiply parentheses

5u-9u+12

We add all the numbers together, and all the variables

-4u+12

Back to the equation:

-(-4u+12)



We add all the numbers together, and all the variables

8u-(-4u+12)+3=0

We get rid of parentheses

8u+4u-12+3=0

We add all the numbers together, and all the variables

12u-9=0

We move all terms containing u to the left, all other terms to the right

12u=9

u=9/12

u=3/4

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