7+2(3)(2x-2)=6(x+7)

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Solution for 7+2(3)(2x-2)=6(x+7) equation: 



7+2(3)(2x-2)=6(x+7)

We move all terms to the left:

7+2(3)(2x-2)-(6(x+7))=0

We multiply parentheses

46x-(6(x+7))-46+7=0



We calculate terms in parentheses: -(6(x+7)), so:

6(x+7)

We multiply parentheses

6x+42

Back to the equation:

-(6x+42)



We add all the numbers together, and all the variables

46x-(6x+42)-39=0

We get rid of parentheses

46x-6x-42-39=0

We add all the numbers together, and all the variables

40x-81=0

We move all terms containing x to the left, all other terms to the right

40x=81

x=81/40

x=2+1/40

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