7+12t+2(2t-1)=2(2t-1)

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Solution for 7+12t+2(2t-1)=2(2t-1) equation: 



7+12t+2(2t-1)=2(2t-1)

We move all terms to the left:

7+12t+2(2t-1)-(2(2t-1))=0

We multiply parentheses

12t+4t-(2(2t-1))-2+7=0



We calculate terms in parentheses: -(2(2t-1)), so:

2(2t-1)

We multiply parentheses

4t-2

Back to the equation:

-(4t-2)



We add all the numbers together, and all the variables

16t-(4t-2)+5=0

We get rid of parentheses

16t-4t+2+5=0

We add all the numbers together, and all the variables

12t+7=0

We move all terms containing t to the left, all other terms to the right

12t=-7

t=-7/12

t=-7/12

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