7+0.4(5y-10)=0.8(y+5)+0.2

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Solution for 7+0.4(5y-10)=0.8(y+5)+0.2 equation: 



7+0.4(5y-10)=0.8(y+5)+0.2

We move all terms to the left:

7+0.4(5y-10)-(0.8(y+5)+0.2)=0

We multiply parentheses

2y-(0.8(y+5)+0.2)-4+7=0



We calculate terms in parentheses: -(0.8(y+5)+0.2), so:

0.8(y+5)+0.2

We multiply parentheses

0.8y+4+0.2

We add all the numbers together, and all the variables

0.8y+4.2

Back to the equation:

-(0.8y+4.2)



We add all the numbers together, and all the variables

2y-(0.8y+4.2)+3=0

We get rid of parentheses

2y-0.8y-4.2+3=0

We add all the numbers together, and all the variables

1.2y-1.2=0

We move all terms containing y to the left, all other terms to the right

1.2y=1.2

y=1.2/1.2

y=1

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