7+(7x-3)=(2x-3)-5+-3

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Solution for 7+(7x-3)=(2x-3)-5+-3 equation: 



7+(7x-3)=(2x-3)-5+-3

We move all terms to the left:

7+(7x-3)-((2x-3)-5+-3)=0

We use the square of the difference formula

(7x-3)-((2x-3)-5-3)+7=0

We get rid of parentheses

7x-((2x-3)-5-3)-3+7=0



We calculate terms in parentheses: -((2x-3)-5-3), so:

(2x-3)-5-3

We add all the numbers together, and all the variables

(2x-3)-8

We get rid of parentheses

2x-3-8

We add all the numbers together, and all the variables

2x-11

Back to the equation:

-(2x-11)



We add all the numbers together, and all the variables

7x-(2x-11)+4=0

We get rid of parentheses

7x-2x+11+4=0

We add all the numbers together, and all the variables

5x+15=0

We move all terms containing x to the left, all other terms to the right

5x=-15

x=-15/5

x=-3

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