7+(4+3y)=-2(4+y)

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Solution for 7+(4+3y)=-2(4+y) equation: 



7+(4+3y)=-2(4+y)

We move all terms to the left:

7+(4+3y)-(-2(4+y))=0

We add all the numbers together, and all the variables

(3y+4)-(-2(y+4))+7=0

We get rid of parentheses

3y-(-2(y+4))+4+7=0



We calculate terms in parentheses: -(-2(y+4)), so:

-2(y+4)

We multiply parentheses

-2y-8

Back to the equation:

-(-2y-8)



We add all the numbers together, and all the variables

3y-(-2y-8)+11=0

We get rid of parentheses

3y+2y+8+11=0

We add all the numbers together, and all the variables

5y+19=0

We move all terms containing y to the left, all other terms to the right

5y=-19

y=-19/5

y=-3+4/5

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