7+(3x+7)=10-2(x-5)+3x

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Solution for 7+(3x+7)=10-2(x-5)+3x equation: 



7+(3x+7)=10-2(x-5)+3x

We move all terms to the left:

7+(3x+7)-(10-2(x-5)+3x)=0

We get rid of parentheses

3x-(10-2(x-5)+3x)+7+7=0



We calculate terms in parentheses: -(10-2(x-5)+3x), so:

10-2(x-5)+3x

determiningTheFunctionDomain
-2(x-5)+3x+10

We add all the numbers together, and all the variables

3x-2(x-5)+10

We multiply parentheses

3x-2x+10+10

We add all the numbers together, and all the variables

x+20

Back to the equation:

-(x+20)



We add all the numbers together, and all the variables

3x-(x+20)+14=0

We get rid of parentheses

3x-x-20+14=0

We add all the numbers together, and all the variables

2x-6=0

We move all terms containing x to the left, all other terms to the right

2x=6

x=6/2

x=3

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