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7(x-1)=2(3x+1)
We move all terms to the left:
7(x-1)-(2(3x+1))=0
We multiply parentheses
7x-(2(3x+1))-7=0
We calculate terms in parentheses: -(2(3x+1)), so:We get rid of parentheses
2(3x+1)
We multiply parentheses
6x+2
Back to the equation:
-(6x+2)
7x-6x-2-7=0
We add all the numbers together, and all the variables
x-9=0
We move all terms containing x to the left, all other terms to the right
x=9
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