7*((10b+2)/4)+1B=133

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Solution for 7*((10b+2)/4)+1B=133 equation: 



7((10b+2)/4)+1=133

We move all terms to the left:

7((10b+2)/4)+1-(133)=0

We add all the numbers together, and all the variables

7((10b+2)/4)-132=0

We multiply all the terms by the denominator


7((10b+2)-132*4)=0

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