7(z-81)=42

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Solution for 7(z-81)=42 equation: 



7(z-81)=42

We move all terms to the left:

7(z-81)-(42)=0

We multiply parentheses

7z-567-42=0

We add all the numbers together, and all the variables

7z-609=0

We move all terms containing z to the left, all other terms to the right

7z=609

z=609/7

z=87

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