7(z+5)=6(z-2)+z

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Solution for 7(z+5)=6(z-2)+z equation: 



7(z+5)=6(z-2)+z

We move all terms to the left:

7(z+5)-(6(z-2)+z)=0

We multiply parentheses

7z-(6(z-2)+z)+35=0



We calculate terms in parentheses: -(6(z-2)+z), so:

6(z-2)+z

We add all the numbers together, and all the variables

z+6(z-2)

We multiply parentheses

z+6z-12

We add all the numbers together, and all the variables

7z-12

Back to the equation:

-(7z-12)



We get rid of parentheses

7z-7z+12+35=0

We add all the numbers together, and all the variables

47!=0

There is no solution for this equation

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