7(z+4)=64+3z

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Solution for 7(z+4)=64+3z equation:


Simplifying
7(z + 4) = 64 + 3z

Reorder the terms:
7(4 + z) = 64 + 3z
(4 * 7 + z * 7) = 64 + 3z
(28 + 7z) = 64 + 3z

Solving
28 + 7z = 64 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
28 + 7z + -3z = 64 + 3z + -3z

Combine like terms: 7z + -3z = 4z
28 + 4z = 64 + 3z + -3z

Combine like terms: 3z + -3z = 0
28 + 4z = 64 + 0
28 + 4z = 64

Add '-28' to each side of the equation.
28 + -28 + 4z = 64 + -28

Combine like terms: 28 + -28 = 0
0 + 4z = 64 + -28
4z = 64 + -28

Combine like terms: 64 + -28 = 36
4z = 36

Divide each side by '4'.
z = 9

Simplifying
z = 9

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